In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?

$△ A B D ≅ △ A C D$ by SAS postulate

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$△ A B D ≅ △ A C D$ by AAS postulate

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AB = AC

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BD = CD

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Solution

The correct option is A
$△ A B D ≅ △ A C D$ by SAS postulate

In $△ A B D$ and $△ A C D$

(i) $∠ A B D = ∠ A C D$ ... (given)

(ii) $∠ B A D = ∠ C A D$ ... (given)

(iii) AD = AD ... (common)

(iv) $△ A B D ≅ △ A C D$ ... (AAS Postulate)

(v) AB = AC ... (cpct)

(vi) BD = CD ... (cpct)

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Similar questions

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?
a) $△ A B D ≅ △ A C D$ by SAS postulate
b) $△ A B D ≅ △ A C D$ by AAS postulate
c)AB = AC
d)BD = CD

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is true ?

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∠ B A D = ∠ C A D

∠ A B D = ∠ A C D

, then which of the following is false?

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In the given figure, if ∠BAD=∠CAD,∠ABD=∠ACD, then which of the following is false?

The correct option is A △ABD≅△ACD by SAS postulate In △ABD and △ACD (i) ∠ABD=∠ACD ... (given) (ii) ∠BAD=∠CAD ... (given) (iii) AD = AD ... (common) (iv) △ABD≅△ACD ... (AAS Postulate) (v) AB = AC ... (cpct) (vi) BD = CD ... (cpct)

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?