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Question

In the given figure, if AOB is a line segment and ∠GOC = ∠HOD = ∠IOE = ∠FOB = 90°, then which of the following is always true?

A
x+c+ab+y+z=1
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B
x+c+b+y=2a+2z
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C
x+c+b+y+a+z=360°
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D
x+y+b+ca+z=3
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Solution

The correct option is B x+c+b+y=2a+2z
Given: ∠GOC = ∠HOD = ∠IOE = ∠FOB = 90°

Since AOB is a straight line.
∴ ∠AOI + ∠IOE + ∠EOB = 180° (Linear pair)
⇒ a + ∠IOE + z = 180°
⇒ a + z = 180° – 90° (∵ ∠IOE = 90°)
⇒ a + z = 90° …..(i)
Similarly, b + y = 90° …..(ii)
and, c + x = 90° …..(iii)
Adding (ii) and (iii), we get
b + y + c + x = 90° + 90°
⇒ x + c + b + y = 180°
⇒ x + c + b + y = 2 × 90°
⇒ x + c + b + y = 2(a + z) [From (i)]
⇒ x + c + b + y = 2a + 2z
Hence, the correct answer is option (b).

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