In the given figure if AP=BP, AQ=BQ, then can we say that AM=BM?
True
In the given figure,
PA=PB (Given)
AQ=BQ (Given)
PQ is common.
So, Δ PAQ ≅ Δ PBQ (SSS rule).
⇒∠ APQ=∠ BPQ (CPCT).
Also, PA=PB (Given) and PM is common
Hence, △ PMA ≅ △PMB (SAS Rule)
So, AM=BM (CPCT)