Question

In the given figure, if ∠BAC = 60° and ∠BCA = 20°, find ∠ADC.

Answer 1

It is given that, and

We have to find the

In given we have

$$\begin{gathered} \angle ABC+\angle BCA+\angle BAC=180°\left(\mathrm{Angle}\mathrm{sum}\mathrm{property}\right) \\ \Rightarrow \angle ABC=180°-\left(60°+20°\right)=100° \end{gathered}$$

In cyclic quadrilateral we have

(Sum of pair of opposite angles of a cyclic quadilateral is 180º)

Then,

Hence