Then which of these following options is correct-A- - ABC - ACFB- - ABE - ACFC- - AEB - ABCD- - ABE - CBF

The correct option is B Δ ABE ≅Δ ACF In Δ ABE and Δ ACF, BE = CF nbsp; [given] ∠ CFA = ∠ BEA = 90^∘ ∠ A is common. Hence, Δ ABE ≅Δ ACF nbsp; [by AAS Criter ...

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Standard IX

Mathematics

Congruency

then which of...

Question

In the given figure, if $B E = C F,$ then which of these following options is correct?

$Δ A B C ≅ Δ A C F$

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$Δ A B E ≅ Δ A C F$

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$Δ A B E ≅ Δ C B F$

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$Δ A E B ≅ Δ A B C$

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Solution

The correct option is B
$Δ A B E ≅ Δ A C F$

In $Δ A B E$ and $Δ A C F,$
$B E = C F$ [given]
$∠ C F A = ∠ B E A = 90^{\circ}$
$∠ A$ is common.
Hence, $Δ A B E ≅ Δ A C F$ [by $A A S$ Criterion]

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Similar questions

In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC.

If $Δ A B E ≅ Δ A C D$ , show that $Δ A D E \sim Δ A B C$ .

Q. In

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and BE is median of

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If ar

(Δ A B E) =

c m^{2}

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Q. In fig, If

Δ A B E ≅ Δ A C D

, show that

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Q. In the below figure, if

Δ A B E ≅ Δ A C D

, show that

Δ A D E \sim Δ A B C

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In the given figure, if BE=CF, then which of these following options is correct?

The correct option is B ΔABE≅ΔACF In ΔABE and ΔACF, BE=CF [given] ∠CFA=∠BEA=90∘ ∠A is common. Hence, ΔABE≅ΔACF [by AAS Criterion]

In the given figure, if $B E = C F,$ then which of these following options is correct?

The correct option is B
$Δ A B E ≅ Δ A C F$

In $Δ A B E$ and $Δ A C F,$
$B E = C F$ [given]
$∠ C F A = ∠ B E A = 90^{\circ}$
$∠ A$ is common.
Hence, $Δ A B E ≅ Δ A C F$ [by $A A S$ Criterion]