In the given figure if BE - CF- then which of these following options is correct- - ABE nbsp- ACF- ABC - AFC- ABC - ACF- ABE - CAF-

The correct option is A Δ ABE nbsp;≅Δ ACF In Δ ABE and Δ ACF, BE = CF [given] ∠ CFA = ∠ BEA = 90^∘ ∠ A is common. Hence, Δ ABE ≅Δ ACF [by A.A.S. Criterion] ...

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Standard IX

Mathematics

ASA

In the given ...

Question

In the given figure if BE = CF, then which of these following options is correct?

$Δ A B C ≅ Δ A C F$

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$Δ A B E ≅ Δ A C F$

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$Δ A B E ≅ Δ C A F$

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$Δ A B C ≅ Δ A F C$

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Solution

The correct option is B
$Δ A B E ≅ Δ A C F$

In $Δ A B E a n d Δ A C F,$
BE = CF [given]
$∠ C F A = ∠ B E A = 90^{\circ}$
$∠ A$ is common.
Hence, $Δ A B E ≅ Δ A C F$ [by A.A.S. Criterion]

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Similar questions

Q. In the given figure, BE and CF are two equal altitudes of ΔABC.
Show that (i) ΔABE ≅ ΔACF, (ii) AB = AC.

$A B C$ is a triangle in which altitudes $B E$ and $C F$ to sides $A C$ and $A B$ are equal (see the given figure). Show that

(i) $△ A B E ≅ △ A C F$

(ii) $A B = A C,$ i.e., $A B C$ is an isosceles triangle.

Q. In the given figure, BE ⊥ CA and CF ⊥ BA such that BE = CF. Then, which of the following is true?
(a) ∆ABE ≅ ∆ACF
(b) ∆ABE ≅ ∆AFC
(c) ∆ABE ≅ ∆CAF
(d) ∆ABE ≅ ∆FAC

In the given figure if BE = CF, then which of these following options is correct?

In the given figure, if $B E = C F,$ then which of these following options is correct?

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In the given figure if BE = CF, then which of these following options is correct?

The correct option is B ΔABE≅ΔACF In ΔABE and ΔACF, BE = CF [given] ∠CFA=∠BEA=90∘ ∠A is common. Hence, ΔABE≅ΔACF [by A.A.S. Criterion]

The correct option is B
$Δ A B E ≅ Δ A C F$

In $Δ A B E a n d Δ A C F,$
BE = CF [given]
$∠ C F A = ∠ B E A = 90^{\circ}$
$∠ A$ is common.
Hence, $Δ A B E ≅ Δ A C F$ [by A.A.S. Criterion]