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In the given ...

Question

In the given figure if blocks A and B will move with same acceleration due to external agent, there is no friction between A and B, then the magnitude of interaction force between the two blocks will be:

A

2 m g / c o s θ

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B

2 m g c o s θ

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C

m g c o s θ

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D

none of these

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Solution

The correct option is A $2 m g / c o s θ$
$\begin{matrix} N sin θ = 2 m a \Rightarrow N = \frac{2 m a}{sin θ} . . . . . . . (1) & N cos θ = 2 m g \Rightarrow N = \frac{2 m g}{cos θ} H e n c e, o p t i o n C i s c o r r e c t a n s w e r . \end{matrix}$

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