In the given figure if -i a - 130- - find b-ii b - 200- - find a-

(i) nbsp;From figure, a + b = 360° ⇒ 130^∘+b= 360^∘ ⇒ b = 360^∘ 130^∘ ⇒ b = 230^∘ (ii) nbsp;From figure, a + b =360^∘ ⇒ a+200^∘= 360^∘ ⇒ a = 360^∘ 200 ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Construction of an Angle using Protractor

In the given ...

Question

In the given figure if :
(i) a = 130° ; find b.
(ii) b = $200^{\circ}$ ; find a.

Open in App

Solution

(i) From figure, a + b = 360°
$\Rightarrow 130^{\circ} + b = 360^{\circ} \Rightarrow b = 360^{\circ} - 130^{\circ} \Rightarrow b = 230^{\circ}$

(ii) From figure,
a + b = $360^{\circ}$
$\Rightarrow a + 200^{\circ} = 360^{\circ} \Rightarrow a = 360^{\circ} - 200^{\circ} \Rightarrow a = 160^{\circ}$

Suggest Corrections

Similar questions

In the given figure, $∠$ A= 130 degrees and $∠$ B= 40 degrees. If $△$ ABC is congruent to $△$ DEF, then find $∠$ F.

In the given figure, AB is the diameter of a circle with centre O. $∠$ = $130^{o}$ . FInd : (i) $∠$ DAB (ii) $∠$ DBA

The figure given below, shows a circle with centre O.

Given : $∠$ AOC = a and $∠$ ABC = b.

(i) Find the relationship between a and b.

(ii) Find the measure fo angle OAB, if OABC is a parallelogram.

In the given figure, if $∠ A O C = 130^{\circ},$ find the value of $∠ A B C$ .

In the given figure, PQRS is a cyclic quadrilateral in a circle with centre O. If $∠ P S R = 130^{\circ}$ . Find $∠ Q P R$ .

Join BYJU'S Learning Program

In the given figure if : (i) a = 130° ; find b. (ii) b = 200∘ ; find a.

(i) From figure, a + b = 360° ⇒ 130∘+b=360∘⇒ b=360∘−130∘⇒ b=230∘ (ii) From figure, a + b =360∘ ⇒ a+200∘=360∘⇒ a=360∘−200∘⇒ a=160∘

In the given figure if :
(i) a = 130° ; find b.
(ii) b = $200^{\circ}$ ; find a.

(i) From figure, a + b = 360°
$\Rightarrow 130^{\circ} + b = 360^{\circ} \Rightarrow b = 360^{\circ} - 130^{\circ} \Rightarrow b = 230^{\circ}$

(ii) From figure,
a + b = $360^{\circ}$
$\Rightarrow a + 200^{\circ} = 360^{\circ} \Rightarrow a = 360^{\circ} - 200^{\circ} \Rightarrow a = 160^{\circ}$