Question

In the given figure if, line $PY$ $\parallel$ side $BC$, $AP=3$, $PB=6$, $AY=6$ and $YC=x$, then find $x$.

Answer 1

In $\Delta ABC$, line $l$ $\parallel$ side $BC$,
By B.P.T., we have
$\frac{AY}{YC}=\frac{AP}{PB}$
$\Rightarrow \frac{6}{x}=\frac{3}{6}$
$\Rightarrow x\times 3=6\times 6$
$\Rightarrow x=\frac{36}{3}$
$\Rightarrow x=12$ units.