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Question

In the given figure, if MN and PQ are parallel, find the value of (∠X + ∠Y).


A
30°
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B
105°
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C
130°
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D
105°
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Solution

The correct option is B 105°


MN and PQ are parallel lines and PN is transversal.
QPN=MNP
[Alternate interior angles]

So, QPN=X=30

Now, Y=PQM + QPN
[Exterior angle property]

Y=45 + 30 Y=75

So, value of X + Y=30+75=105


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