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Question

In the given figure if 'O' is the centre of the circle then AOB =___


A

260

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B

100

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C

50

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D

None of the above

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Solution

The correct option is C

100


Give OAC=20 and OBC=30

Let us draw aa line joining 'O' and 'C'

Now in Δ OAC

OA = OC

OCA= OAC

OCA=20

Similarly in Δ BOC

OB = OC

OCB= OBC

OCB=30

ACB= OCA+ OCB

=20+30

=50

Now AOB=2× ACB

(because The angle subtends by arc at centre is twice that it subtends at any point on the remaining part of circumference)

AOB=2×50

=100


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