In the given figure, if OA = BO and OC = OD, then, ΔAOD ≅ ΔBOC by __ congruence rule.
In ΔAOD and ΔBOC, we have,
OA = OB (given)
OD = OC (given)
∠AOD = ∠BOC (vertically opposite angles)
Therefore, ΔAOD ≅ ΔBOC (by S.A.S. congruence condition)
In the given figure, if OA = BO and OC = OD, then, ΔAOD≅ΔBOC by SAS congruence rule.