In the given figure, if OA = OB and OC = OD, then $△ A O D ≅ △ B O C$ by ____ criterion of congruency.

ASA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

RHS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

SAS

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

SSS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C SAS

In $△ A O D$ and $△ B O C$ we have,
OA = OB (given)
OC = OD (given)
$∠ C O B = ∠ D O A$ ..... (vertically opposite angles included between the corresponding sides)

Therefore, $△ A O D ≅ △ B O C$ by SAS criterion for congruency of triangles.

Suggest Corrections

Similar questions

O A = O B, O D = O C

Δ A O D ≅ Δ B O C

△ A O D ≅ △ B O C

=

=

Δ A O D ≅ Δ B O C

In the given figure, if OA = BO and OC = OD, then, $△$ AOD $≅$ $△$ BOC by __ congruence rule.

In figure , if OA = OB, OD= OC then ∆AOD ≅ ∆BOC by congruence rule:

Join BYJU'S Learning Program