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Theorem 3: Opposite Angles in a Parallelogram Are Equal

In the given ...

Question

In the given figure, if parallelogram ABCD and rectangle ABEF are of equal area then:

A

Perimeter of ABCD < perimeter of ABEF

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B

Perimeter of ABCD = perimeter of ABEF

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C

Perimeter of ABCD = ¹/₂ (perimeter of ABEF)

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D

Perimeter of ABCD > perimeter of ABEF

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Solution

The correct option is D
Perimeter of ABCD > perimeter of ABEF

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