Question

In the given figure, if PQ is the diameter, then x is equal to ?

• A. ${30}^0$
• B. ${45}^0$
• C. ${70}^0$
• D. ${60}^0$

Answer 1

The correct option is D ${60}^0$



$\angle RPC=\angle PRC={30}^0$ [ Equal angles opp to equal radii of the circle]
$x+\angle PRC={90}^0$ [ Radius of the circle is always perpendicular to the tangent.]
$X+30=90$
$X=90-30={60}^0$
Hence, d is the correct option.