Question 41
In the given figure, if PQ|| RS and QR || TS, then the value of a is
(a) 95∘
(b) 90∘
(c) 85∘
(d) 75∘
Since, PQ ||RS and QR is transversal.
∴∠PQR=∠SRQ⇒∠SRQ=85∘
Also, ST || QR and RS is transversal.
∴∠SRQ=∠RST
Now ∠RST + a = 180∘⇒∠RST + a = 180∘⇒a = 180∘−85∘⇒a = 95∘