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Question

In the given figure, if PR is tangent to the circle at P and Q is the centre of the circle, then ∠POQ =


(a) 110°

(b) 100°

(c) 120°

(d) 90°

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Solution

We know that the radius is always perpendicular to the tangent at the point of contact.

Therefore, we have,

It is given that,

That is,

Now, consider. We have,

OP = OQ (Radii of the same circle)

Since angles opposite to equal side will be equal in a triangle, we have,

We know that sum of all angles of a triangle will be equal to .

Therefore,

The correct answer is option (c).


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