Relationship between Unequal Sides of Triangle and the Angles Opposite to It.
In the given ...
Question
In the given figure, if PR > PQ and PS bisects ∠QPR, then what is the relation between ∠PSR and ∠PSQ?
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A
∠PSR = 0.75 ∠PSQ
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B
∠PSR > ∠PSQ
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C
∠PSR = 0.5 ∠PSQ
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D
∠PSR < ∠PSQ
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Solution
The correct option is B∠PSR > ∠PSQ PR>PQ (Given) ∠PQR > ∠PRQ.........(1) (In any triangle, the angle opposite to the longer side is larger.) We also have ∠PQR+∠QPS+∠PSQ=180∘ (Angle sum property of triangle) ∴∠PQR=180∘−∠QPS−∠PSQ.....(2) And, ∠PRQ+∠RPS+∠PSR=180∘ (Angle sum property of triangle) ∴∠PRQ=180∘−∠PSR−∠RPS .........(3) Substituting (2) and (3) in (1), we get 180∘−∠QPS−∠PSQ>180∘−∠PSR−∠RPS We also have ∠QPS=∠RPS, using this in the above equation, we get −∠PSQ > −∠PSR ⇒∠PSQ < ∠PSR ⇒∠PSR>∠PSQ