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Question

In the given figure, if PR > PQ and PS bisects QPR, then what is the relation between PSR and PSQ?

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A
PSR = 0.75 PSQ
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B
PSR > PSQ
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C
PSR = 0.5 PSQ
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D
PSR < PSQ
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Solution

The correct option is B PSR > PSQ
PR>PQ (Given)
PQR > PRQ.........(1) (In any triangle, the angle opposite to the longer side is larger.)
We also have PQR+QPS+PSQ=180 (Angle sum property of triangle)
PQR=180QPSPSQ.....(2)
And, PRQ+RPS+PSR=180 (Angle sum property of triangle)
PRQ=180PSRRPS .........(3)
Substituting (2) and (3) in (1), we get
180QPSPSQ>180PSRRPS
We also have QPS=RPS, using this in the above equation, we get
PSQ > PSR
PSQ < PSR
PSR>PSQ

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