wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, if quadrilateral PQRS circumscribes a circle, then PD + QB =


(a) PQ

(b) QR

(c) PR

(d) PS

Open in App
Solution

We know that tangents drawn to a circle from the same external point will be equal in length.

Therefore,

PD = PA …… (1)

QB = QA …… (2)

Adding equations (1) and (2), we get,

PD + QB = PA + QA

By looking at the figure we can say,

PD + QB = PQ

Therefore option (a) is the correct answer.


flag
Suggest Corrections
thumbs-up
54
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon