In the given figure, if $r ∥ s, p ∥ q$ and $u ∥ t$ , then $c$ equals

a - b

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2 a + b

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a + b

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b - a

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Solution

The correct option is C $a + b$
we know that,

outer angle = sum of inner angles.

Therefore, $c = a + b$

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Similar questions

p, q, r, s, t

u

(t - r)

A = {p, q, r, s}

B = {r, s, t, u}

A / B

\begin{matrix} Table-1 & Table-2 (A) Velocity - time graph & (P) Slope \to negative (B) Acceleration - time graph & (Q) Slope \to positive (C) Displacement - time graph & (R) Slope \to zero (S) | Slope | \to increasing (T) | Slope | \to decreasing (U) | Slope | \to constant \end{matrix}

(a) If A = {p, q, r, s), B = (s, t, u) and C = (s, t, u, v, w}

Find (i) A ∪ (B ∪ C) (ii) (A ∪ B) ∪ C (iii) A ∩ (B ∩ C) (iv) (A ∩ B) ∩ C

(b) If A = {1, 4, 9, 16}, B = {3, 4, 5} and C = {3, 9, 12}

Verify (i) A ∪ (B ∪ C) = (A ∪ B) ∪ C (ii) A ∩ (B ∩ C) = (A ∩ B) ∩ C

Verify (i) A ∪ (B ∪ C) = (A ∪ B) ∪ (A ∪ C), (ii) A ∩ (B ∩ C) = (A ∩ B) ∩ (A ∩ C)

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