In the given figure- if AB-CD- APQ-50- and - PRD-127-the value of y is-

Given AB and CD are parallel lines. PR acts here as a transversal. Then, ∠ APR=∠ PRD nbsp; nbsp; nbsp;[alternate interior angles] ⇒ 50^∘+y=127^∘ ⇒ y=77^ ...

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Standard IX

Mathematics

Exterior Angle Property

In the given ...

Question

In the given figure, if $AB||CD, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ ,
the value of y is:

77°

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127°

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130°

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50°

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Solution

The correct option is A 77°

Given AB and CD are parallel lines. PR acts here as a transversal.

Then,
$∠ A P R = ∠ P R D$ [alternate interior angles]
$\Rightarrow 50^{\circ} + y = 127^{\circ}$
$\Rightarrow y = 77^{\circ}$

So, value of y is 77°.

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In the given figure, if AB||CD, ∠APQ=50∘ and ∠PRD=127∘, the value of y is:

The correct option is A 77° Given AB and CD are parallel lines. PR acts here as a transversal. Then, ∠APR=∠PRD [alternate interior angles] ⇒50∘+y=127∘ ⇒y=77∘ So, value of y is 77°.

In the given figure, if $AB||CD, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}$ ,
the value of y is:

The correct option is A 77°

Given AB and CD are parallel lines. PR acts here as a transversal.

Then,
$∠ A P R = ∠ P R D$ [alternate interior angles]
$\Rightarrow 50^{\circ} + y = 127^{\circ}$
$\Rightarrow y = 77^{\circ}$

So, value of y is 77°.