Question

In the given figure, if the altitude and the base of parallelogram are 12 cm and 6 cm respectively, then the area of $△BEC$ is:

• A. $16c{m}^2$
• B. $26c{m}^2$
• C. $36c{m}^2$
• D. $46c{m}^2$

Answer 1

The correct option is C

$36c{m}^2$

area of parallelogram ABCD = $base\times height$
= $12\times 6$
= 72 cm${}^2$
If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangle is equal to half the area of the parallelogram.

$\therefore$ Area of $△$BEC = $\frac{1}{2}$ (Area of ABCD)

Now, $△$BEC = $\frac{1}{2}\times$ 72 cm ${}^2$

$\therefore$ Area of $△$BEC = $36c{m}^2$