Question

In the given figure, if the area of parallelogram $ABEF$ is $96c{m}^2$ then the area of parallelogram $ABCD$ in $c{m}^2$ is:

Answer 1

In given figure $AB||CD||EF$ and $AB=CD=EF$

In parallelogram $ABCD$ and $ABEF$ Base line $AB$ is common

And height parallelogram $ABCD$ and $ABEF$ is because both parallelogram lies between two parlor lines

Then area of parallelogram $ABCD$ and $ABEF$ is equal

Because we know that area parallelogram=$base\times height$

Then area of parallelogram $ABCD$ = $ABEF$ =$96$ sq cm