In the given figure, if the area of triangle $P Q R$ is $100 c m^{2}$ and the altitude $Q T$ is $10 c m$ , then find the value of PR. [2 marks]

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Solution

We know that,

Area of triangle $= \frac{1}{2} \times Base \times Height$ (1 mark)

From the given details, we have,

Area of triangle $P Q R = 100 c m^{2}$

Height of the triangle (altitude) $= 10 c m$

Therefore,

$100 = \frac{1}{2} \times P R \times 10$

$P R = \frac{100 \times 2}{10}$

$P R = \frac{200}{10}$

$P R = 20 c m$ (1 mark)

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^{2}

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In the given figure, if the area of triangle PQR is 100 cm2 and the altitude QT is 10 cm, then find the value of PR. [2 marks]

We know that, Area of triangle =12×Base×Height (1 mark) From the given details, we have, Area of triangle PQR=100 cm2 Height of the triangle (altitude) =10 cm Therefore, 100=12×PR×10 PR=100×210 PR=20010 PR=20 cm (1 mark)

In the given figure, if the area of triangle $P Q R$ is $100 c m^{2}$ and the altitude $Q T$ is $10 c m$ , then find the value of PR. [2 marks]