Question

In the given figure, if the curve is represented by $x^2+x+1$, then the shortest distance of vertex A from the x - axis is

• A. 3 units
• B. $\frac{1}{2}$ units
• C. $\frac{3}{4}$ units
• D. 1 unit

Answer 1

The correct option is C $\frac{3}{4}$ units

Given curve is $x^2+x+1$.
$\therefore$ The shortest distance of vertex A from the x - axis is y - coordinate of A, i.e.

$\frac{-D}{4a}=\frac{-(b^2-4ac)}{4a}$
$=\frac{-(1^2-4\times 1\times 1)}{4\times 1}$
$=\frac{3}{4}$