Question

In the given figure, if the heat flowing through the 5 $ohm$ resistance is 10 calorie then how much heat is flowing through the 4 $ohm$ resistance ?

• A. 1 calorie
• B. 2 calorie
• C. 3 calorie
• D. 4 calorie

Answer 1

The correct option is B 2 calorie

We know that Heat =$I^{2}Rt$

Here,

$H_5=10cal$

In given circuit $5\Omega \parallel \left(4\Omega \&6\Omega \right)$

Therefore,

Voltage across both terminal will be same and current following through 4 and 6 ohm will be same as both are connected in series

Current following through $4\Omega$ will be half of the current following through $5\Omega$ Because resistance is inversely proportional to current.

$H_5=I^2{R}_{5}t$

Substitute all value in above equation

$10=I^{2}5t{I}^{2}t=2$

Similarly,

$H_4={\left(\frac{I}{2}\right)}^{2}4t{H}_4=\frac{I^2}{4}\times 4t=I^{2}t=2cal/sec$

Hence,option (B) is correct option