Question

In the given figure., if $△ABE\cong △ACD$, show that $△ADE\sim △ABC.$

Answer 1

Given $△ABE\cong △ACD$

$\therefore$ $AB=AC$ $.........\left(1\right)$

Also, $AE=AD$ $.........\left(2\right)$

From $\left(1\right)$ and $\left(2\right)$,

$\frac{AB}{AD}=\frac{AC}{AE}$ and

$\angle A$ is Common

$\therefore$ By SAS Criterion of Similarity, $△ADE\sim △ABC$ $\left[henceproved\right]$