Question

In the given figure if $\underset{–}{PTQ}={50}^{\circ }$ find $\underset{–}{POQ}$

Answer 1

$\angle OPT=\angle OQT={90}^o$

(Tangents of circle)

So $\angle POQ+{90}^o+{90}^o+{50}^o={360}^o$

$\angle POQ={360}^o-{230}^o$

$\angle POQ={130}^o$.