Question

Question 108

In the given figure, l m and n are parallel lines, and the lines p and q are also parallel find the values of a, b and c.

Answer 1

Since, lines l, n are parallel and q is transversal.
Therefore, $6a={120}^{\circ }\left[correspondingangles\right]\Rightarrow a=\frac{{120}^{\circ }}{6}\Rightarrow a={20}^{\circ }$
Also, lines p,q are parallel and n is transversal.
$Therefore,4c={120}^{\circ }\left[correspondingangles\right]\Rightarrow c=\frac{{120}^{\circ }}{4}\Rightarrow c={30}^{\circ }$
Again, lines m, n are parallel and p is transversal,
therefore$4c=3b\left[correspondingangles\right]\Rightarrow b=\frac{4c}{3}\Rightarrow =\frac{4\times {30}^{\circ }}{3}\Rightarrow b={40}^{\circ }$