In the given figure- line AB and CD intersect at O- If - COB - x - - BOD -4 x - and - AOD - y - then y -A- 42-B- 18-C- 30-D- 36-

The correct option is D 36^∘(i) ∠ COB + ∠ BOD = 180^∘ ...(linear pair) x^∘+4x^∘ =180^∘ 5x^∘=180^∘ x=36^∘ (ii) ∠ AOD = ∠ COB ...(vertically opposite ...

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Byju's Answer

Standard VI

Mathematics

Straight Line Angle

In the given ...

Question

In the given figure, line AB and CD intersect at O. If $∠ C O B = x^{\circ}$ , $∠ B O D = 4 x^{\circ}$ and $∠ A O D = y^{\circ}$ , then y= ______ .

18^{\circ}

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30^{\circ}

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36^{\circ}

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42^{\circ}

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Solution

The correct option is C $36^{\circ}$
(i) $∠ C O B + ∠ B O D = 180^{\circ}$ ...(linear pair)

$x^{\circ} + 4 x^{\circ} = 180^{\circ}$

$5 x^{\circ} = 180^{\circ}$

$x = 36^{\circ}$

(ii) $∠ A O D = ∠ C O B$ ...(vertically opposite angles)

$∴ y = x = 36^{\circ}$

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Similar questions

Q. In the given figure, straight lines AB and CD intersect at O. If ∠AOC + ∠BOD = 130°, then ∠AOD = ?
(a) 65°
(b) 115°
(c) 110°
(d) 125°

In the figure below, lines AB and CD intersect each other at point O. Angles ( $∠$ AOD, $∠$ COB) and ( $∠$ AOC, $∠$ BOD) are called ___.

Q. In the figure, lines

A B

and

C D

intersect at

O

. If

∠ A O D : ∠ D O B = 4 : 5,

then

∠ C O B

is :

In the figure below, lines AB and CD intersect each other at point O. The angle pairs ( $∠ A O D$ and $∠ C O B$ ) and ( $∠ A O C$ and $∠ B O D$ ) are called ___.

Q. Two lines AB and CD intersect at O. If ∠AOC + ∠COB + ∠BOD = 270°, then ∠AOC =

(a) 70°

(b) 80°

(c) 90°

(d) 180°

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In the given figure, line AB and CD intersect at O. If ∠COB=x∘, ∠BOD=4x∘ and ∠AOD=y∘, then y= ______ .

The correct option is C 36∘(i) ∠COB+∠BOD=180∘ ...(linear pair) x∘+4x∘=180∘ 5x∘=180∘ x=36∘ (ii) ∠AOD=∠COB ...(vertically opposite angles) ∴y=x=36∘

In the given figure, line AB and CD intersect at O. If $∠ C O B = x^{\circ}$ , $∠ B O D = 4 x^{\circ}$ and $∠ A O D = y^{\circ}$ , then y= ______ .

The correct option is C $36^{\circ}$
(i) $∠ C O B + ∠ B O D = 180^{\circ}$ ...(linear pair)

$x^{\circ} + 4 x^{\circ} = 180^{\circ}$

$5 x^{\circ} = 180^{\circ}$

$x = 36^{\circ}$

(ii) $∠ A O D = ∠ C O B$ ...(vertically opposite angles)

$∴ y = x = 36^{\circ}$