Let us mark the points R and S on line n, T and U on line p, A and B on line l and C and D on line m.
Suppose the lines n and p intersect the line l at K and L respectively and line m at M and N respectively.
Since, the line l and line p intersect at L, then
∠KLN=∠BLT (Vertically opposite angles)
⇒∠KLN=45∘
Since, line l ∥ line m and line p is a transversal intersecting them at L and N, then
∠KLN+∠MNL=180∘ (Pair of interior angles on the same side of transversal is supplementary)
⇒45∘+∠a=180∘
⇒∠a=180∘−45∘=135∘
Since, the line m and line p intersect at N, then
∠DNU=∠MNL (Vertically opposite angles)
⇒∠b=∠a=135∘
Since, line n ∥ line p and line m is a transversal intersecting them at M and N, then
∠NMS=∠DNU (Corresponding angles)
⇒∠c=∠b=135∘