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Byju's Answer
Standard VII
Mathematics
Major Arc, Minor Arc and Semicircular Arc
In the given ...
Question
In the given figure m(arc AXB) = 120°. Find m(arc AYB)
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Solution
m(arc AXB) + m(arc AYB) = 360°
→
m
(
a
r
c
A
Y
B
)
=
360
°
−
m
(
a
r
c
A
X
B
)
→
m
(
a
r
c
A
Y
B
)
=
360
°
−
120
°
=
240
°
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1
Similar questions
Q.
If arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 120
∘
then m(arc AYB) =
Q.
A, B, C are any points on the circle with centre O. m(arc BC)=120
∘
and m(arc AB)=130
∘
.
Then, find the value of m(arc ABC) .
Q.
Vertex C, of
∠
P
C
Q
=
x
lies on the circle. The arms of
∠
P
C
Q
intersect the circle at A and B. If m(arc AB)= 120
∘
, then
x
=
Q.
If vertex C, of
∠
P
C
Q
=
x
lies on the circle. The arms of
∠
P
C
Q
intersect the circle at A and B. If m(arc AB)= 120
∘
, then find the value of
x
.
Q.
In the given figure, O is the centre of the circle. m(arc PQR)=
60
0
OP= 10 cm. Find the area of the shaded region.
(
π
=
3.14
,
√
3
=
1.73
)
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