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Major Arc, Minor Arc and Semicircular Arc

In the given ...

Question

In the given figure m(arc AXB) = 200°. Find m(arc AYB).

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Solution

m(arc AXB) + m(arc AYB) = 360°
$\to m (a r c A Y B) = 360 ° - m (a r c A X B)$
$\to m (a r c A Y B) = 360 ° - 200 °$
$= 160 °$

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