In the given figure, O is equidistant from the sides AC and AB. Then the value of x - 3 is ___.

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Solution

$In Δ A O C and Δ A O B, O C = O B (Given) ∠ O B C = ∠ O C A (Both angles are right angles) And A O is common side . Hence, Δ A O C ≅ Δ A O B (RHS congruence) ∴ ∠ C A O = ∠ B A O (CPCT) \Rightarrow 2 x + 24 = 30 \Rightarrow x = 3 \Rightarrow x - 3 = 0$

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Similar questions

The given figure shows a triangle ABC in whcih AD bisects angle BAC. EG is perpendicular bisector of side AB which intersects AD at point F.

Prove that:

(i) F is equidistant from A and B.

(ii) F is equidistant from AB and AC.

In the given figure, O is equidistant from the sides AC and AB. Then the value of x - 3 is ___.

O is equidistant from the sides AC and AB. Find the value of x - 3.

△ A B C

n (P \cap Q)

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