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Angle Subtended by Diameter on the Circle

In the given ...

Question

In the given figure, O is the centre of a circle, BC is a diameter and ∠BAO = 60°. Then, ∠ADC = ?
(a) 30°
(b) 45°
(c) 60°
(d) 120°

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Solution

(c) 60°

OA = OB
∠ABO = ∠BAO = 60°
∴ ∠ADC = ∠ABO = 60° (Angles in the same segment)

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Similar questions

∠ B A O = 60^{\circ}

∠ A D C

30^{\circ}

45^{\circ}

60^{\circ}

120^{\circ}

B C

∠ B A O = 60^{o} .

∠ A D C

In the given figure, O is the centre of a circle and $∠ A O C = 120^{\circ} .$ Then, $∠$ BDC = ?

(a) $60^{\circ}$

(b) $45^{\circ}$

(d) $15^{\circ}$

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