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Question

In the given figure, O is the centre of the circle. A is any point on minor arc BC. Find the value of BACOBC.



A
90
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B
120
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C
60
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D
45
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Solution

The correct option is A 90
Here OB = OC = radius
ΔOBC is isosceles
OBC=OCB=y
Now in ΔOBC, by angle sum property
OBC+OCB+BOC=180
y+y+t=180
2y+t=180
2y+(360z)=180 [z is the reflex of t]
2y+360z=180




Reflex z=2x [By degree measure theorem]
2y+3602x=1802y2x=1803602y2x=180yx=90xy=90
Thus BACOBC=90


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