Question

In the given figure, O is the centre of the circle. AB is the tangent to the circle at the point P. If $\angle$ PAO = ${30}^o$ then $\angle$ CPB + $\angle$ ACP is equal to

(a) ${60}^o$ (b) ${90}^o$ (c) ${120}^o$ (d) ${150}^o$

Answer 1

APB is a straight line.
<APD+< DPC+<CPB=180°
<APD=<ACP
<ACP+90°+<CPB=180°
<ACP+<CPB=90°

option (b) 90° is correct answer