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Question

In the given figures, O is the centre of the circle and AB is a tangent to it at point B. BDC = 650 Find BAO.


A

40°

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B

60°

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C

30°

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D

50°

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Solution

The correct option is A

40°


Let, BAO = x0

ABO = 900 [ OB AB]

In ΔBDC,

B + D + C = 1800(sum of the angles of triangle)

C = 1800900650=250

Now, BOE = 2C = 500

So, In ΔABO,

A + B + O = 1800

A = 1800900500=400

So, BAO = 400


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