In the given figure, O is the centre of the circle and $∠ O B C = 50^{o}$ . Then $∠ B O C$ is

∠ B O C = 100^{o}

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∠ B O C = 80^{o}

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∠ B O C = 40^{o}

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∠ B O C = 120^{o}

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Solution

The correct option is B $∠ B O C = 80^{o}$
$G i v e n - O i s t h e c e n t r e o f a c i r c l e i n w h i c h Δ A B C h a s b e e n i n s c r i b e d .$

$O B & O C h a s b e e n j o i n e d . ∠ O B C = 50^{o} .$

$T o f i n d o u t - ∠ B A C = ?$
$S o l u t i o n - O B = O C (r a d i i o f t h e s a m e c i r c l e)$

$∴ Δ O B C i s a n i s o s c e l e s o n e w i t h B C a s b a s e .$

$i . e ∠ O B C = ∠ O C B = 50^{o} .$

$∴ ∠ B O C = 180^{o} - (∠ O B C + ∠ O C B) = 180^{o} - (50^{o} + 50^{o}) = 80^{o} .$

$A n s - O p t i o n B$

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