In the given figure, O is the centre of the circle. Chord CD is parallel to the diameter AB. If ∠ABC = 350, calculate ∠CED
20°
Given ∠ABC = 350 and AB ll CD
∴ ∠BCD = ∠ABC = 350 (Alternate intrior angle)
Join O to C and D
∠AOC = 2∠ABC and ∠BOD = 2 ∠BCD (The angle at the centre of a circle is twice the angle at the circumference if both angles stand on the same arc)
⇒ ∠AOC = 2× 350=700
Also, ∠AOC + ∠ COD + ∠BOD = 1800 (Angles on the straight line)
⇒700 +∠COD+700=1800
⇒∠COD = 400
⇒2∠CED = 400
⇒ ∠CED = 200