In the given figure, O is the centre of the circle. Find x.
40°
The angle subtended by an arc at the centre is double than the angle subtended by it at any point on the remaining part of the circle.
⇒∠AOC=2∠ABC [∠ABC=50∘]
⇒∠AOC=2×50∘=100∘
∠OAC=∠OCA [OA = OC (radii of circle)]
In △AOC,
x+x+∠AOC=180∘ [Angle sum property]
⇒2x=180∘−100∘
⇒x=40∘