Question

In the given figure, O is the centre of the circle, $OA=10$ cm and $OC=6$ cm. The length of AB is :

• A. 10 cm
• B. 8 cm
• C. 12 cm
• D. 16 cm

Answer 1

The correct option is D 16 cm

Given $OA=10cm$

$OC=6cm$

$\angle OCA$= ${90}^{\circ }$

By Pythagoras theorem,

$A{C}^2={OA}^2-O{C}^2$

$={10}^2-6^2$

$AC=8cm$

We know that perpendicular from centre of circle bisects the chord

Therefore $AB=2AC$

$AB=16cm$

option D is the answer.