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Byju's Answer
Standard IX
Mathematics
Perpendicular from the Center to a Chord Bisects the Chord
In the given ...
Question
In the given figure,
O
is the centre of the circle
O
B
=
5
cm
. Distance from
O
to chord
A
B
is
3
cm
. Find the length of
A
B
.
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Solution
Radius of given circle
=
O
B
=
O
A
=
5
cm
O
P
=
3
cm
If a perpendicular is dropped from center of the circle on a chord, it bisects the chord.
⟹
A
B
=
2
A
P
In right angles triangle
O
A
P
, using pythagoras theorem:
A
P
=
√
O
A
2
−
O
P
2
A
P
=
√
5
2
−
3
2
=
4
cm
A
B
=
2
×
4
cm
=
8
cm
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Standard IX Mathematics
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