In the given figure, O is the centre of the circle, the value of x is
55∘
We have ∠QPS=90∘ [Angles in a semicircle]
In ΔPQS
∠PSQ+∠SQP+∠QPS=180∘ [Sum of angles of a triangle is 180∘]
⇒∠PSQ=180∘−90∘−35∘=55∘
Then, x = ∠PSQ [Angles in the same segment]
=55∘