In the given figure, O is the centre of the sector. $∠$ ROQ = $∠$ MON = 60^° . OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. ( $π = \frac{22}{7}$ )

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Solution

In the given figure, ∠ROQ = ∠MON = θ = 60º

Radius of the sector ORXQ = OR = 7 cm

∴ Length of the arc RXQ = $\frac{θ}{360 °} \times 2 π r = \frac{60 °}{360 °} \times 2 \times \frac{22}{7} \times 7$ = 7.3 cm

Radius of the sector OMYN = OM = 21 cm

∴ Length of the arc MYN = $\frac{θ}{360 °} \times 2 π r = \frac{60 °}{360 °} \times 2 \times \frac{22}{7} \times 21$ = 22 cm

Thus, the lengths of the arc RXQ and arc MYN are 7.3 cm and 22 cm, respectively.

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In the given figure, O is the centre of the sector. ∠ROQ = ∠MON = 60° . OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. ( π=227)

In the given figure, O is the centre of the sector. $∠$ ROQ = $∠$ MON = 60^° . OR = 7 cm, and OM = 21 cm. Find the lengths of arc RXQ and arc MYN. ( $π = \frac{22}{7}$ )