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Question

In the given figure, O is the centre of two concentric circles of radii 3 cm and 5 cm. AB is a chord of the outer circle, which touches the inner circle. The length of AB is


(a) 4 cm
(b) 7 cm
(c) 8 cm
(d) 34cm

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Solution

(c) 8 cm

Given, OP=3 cm and OA=5 cmNow, OPA=OPB=900(Tangents drawn from an external point are perpendicular to the radius at the point of contact)In OPA,OA2=(OP2+AP2)OA2-OP2=AP252-32=AP2AP2=16AP=16AP=4cmAB=2×APcm=2×4cm=8cm (Perpendicular drawn from the centreto a chord bisects the chord)

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