Question

In the given figure OA, OB are opposite rays and $\angle AOC+\angle BOD={90}^{\circ }$, then $\angle COD$ is

• A. ${90}^{\circ }$
• B. ${60}^{\circ }$
• C. ${45}^{\circ }$
• D. ${30}^{\circ }$

Answer 1

The correct option is A ${90}^{\circ }$

In the given figure, $\angle AOC+\angle BOD+\angle COD={180}^{\circ }$
Given, $\angle AOC+\angle BOD={90}^{\circ }$
Thus, $\angle COD=180-90={90}^{\circ }$