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Question

# In the given figure OABC is a rhombus, three of whose vertices lie on a circle with center O. If the area of the rhombus is 50√3 cm2, then the area of the circle is sq cm. (Take π=3.14)

A

31.4

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B

300

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C

314

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D

341

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Solution

## The correct option is C 314 Join OB we know OA = OC = OB (radius of same circle) Also, OA = AB = BC = CO (ABCD is a rhombus ) Hence the rhombus can be divided into two equilateral △'s Area of Rhombus = 2(√32 r2) 50/√3=/2(√3/42)r2 r2=100⇒r=10cm Area of circle = πr2 =(3.14)(10) =314cm2

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