Question

In the given figure, OABC is a square of side 7 cm. If COPB is a quadrant of a circle with centre C find the area of the shaded region.

Answer 1

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We have,
length of each side of square OABC = s = 7 cm
Now,
$areaofsquare=s^2=49{cm}^2$

Now, radius of quadrant OAPC = r = 7 cm

Now, area of quadrant OAPC =$\pi \frac{r^2}{4}=\frac{1}{4}\times \frac{22}{7}\times 7\times 7=38.5{cm}^2$
Now, area of shaded region = area of square OABC − area of quadrant OAPC = 49 − 38.5 = $10.5{cm}^2$