In the given figure, P and Q are the centres of two circles intersecting at B and C. ACD is a straight line. Calculate the numerical value of x.
130∘
In the given figure,
∠APB=2∠ACB [Angle subtended by an arc at the center is double the angle subtended by it at any other point on the remaining part of the circle]
⇒∠ACB=65∘
Now, ∠ACB+∠BCD=180∘ [Linear pair angles]
⇒BCD=115∘
∴ Reflex∠BQD=2∠BCD=2×115∘=230∘
Also, x + Reflex∠BQD=360∘
⇒x+230∘=360∘
⇒x=360∘−230∘=130∘